The reaction,`2NO(g)+O_(2)(g)hArr2NO_(2)(g),` is of first order. If the volume of reaction vessel is reduced to `(1)/(3)`, the rate of reaction would be

The reaction 2NO(g)+O_(2)(g)rarr2NO_(2)(g) is of first order. Ifvolume of reaction vessel is reduced to 1/3, the rate of reaction would become

The reaction A to products is of first order . If volume of reaction vessel is reduced to 1/3 , the rate of reaction would be _______.

The reaction A to products is of first order . If volume of reaction vessel is reduced to 1/3 , the rate of reaction would be _______.

For a reaction NO_(g) +O_(2) (g) rarr 2NO_(2)(g) Rate =k[NO^(2)] [O_(2)] if the volume of the reaction vessel is doubled the rate of the reaction :

Using rate law, how much rate of reaction: 2NO(g) + O_(2)(g) to 2NO_(2)(g) will change if the volume of vessel is reduced to 1/3 rd of its initial value ?

For a reaction 2NO (g) + O_2 (g) to 2 NO_2 (g) Rate= k [NO]^2 [O_2] , if the volume of the reaction vessel is double. What is the rate of reaction.

Show by uisng rate laws how much the rate of reaction 2NO(g) + O_(2)(g) rarr 2NO(g) will change if the volume of the reaction vessel is diminished to 1//3 of its initial volume.