x के सापेक्ष अवकलन कीजिए -
`e^(x)sinx+e^(x)cosx`

int e^(x).(1+sinx)/(1+cosx)dx

int e^x(sinx+cosx)dx=

int e^(2x) (2sinx + cosx) dx =

int e^x sin x(sinx + 2cosx)dx =

int(e^x(1-sinx))/(1-cosx)dx

int e^(x)[(1+sinx cosx)/(cos^(2)x)]dx

int e^x ((1+sinx)/(1+cosx))dx=

e^(x)((cosx-sinx)/(sin^(2)x))

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. The f(x)+g(x) has the value equal to a) e^(x)+sinx+2x b) e^(x)+sinx c) e^(x)-sinx d) e^(x)+sinx+x

∫e^x (Cosx + Sinx) dx