A rigid and a disc of different masses are rotating with the same kinetic energy. If we apply a retarding torque `tau` on the ring, it stops after making n revolution. After how many revolutions will the disc stop, if the retarding torque on it is also `tau` ?

A ring and a disc of different masses are rotating with the same kinetic energy. If we apply a retarding torque tau on the ring, it stops after making n revolution. After how many revolutions will the disc stop, if the retarding torque on it is also tau ?

A ring and a disc of different masses are rotating with the same kinetic energy. If we apply a retarding torque r on the ring and the ring stops after making n revolutions, then in how many revolutions will the disc stop under the same retarding torque ?

A ring and a disc of different masses are rotating with the same kinetic energy. If a retarding torque (tau) is applied to the ring, the ring stops after completing n rotations. If the same retarding torque is applied to the disc, how many rotations would it complete before coming to rest?

A ring, a solid sphere and a thin disc of different masses rotate with the same kinetic energy. Equal torques are applied to stop them. Which will make the least number of rotations before coming to rest?

A ring, a solid sphere and a thin disc of different masses rotate with the same kinetic energy. Equal torques are applied to stop them. Which will make the least number of rotations before coming to rest?

Two objects have different masses but the same kinetic energy. If you step them with the same retarding force, which one will stop in the shorter distance?

If a body starts rotating from rest because of a torque of 2 Nm, then its kinetic energy after 20 revolutions will be

A fan is rotating at 90rmp. It is then switched OFF . It stops after 21 revolutions. Calculate the time taken by it to stop assuming that the frictional torque is constant.

If a body starts rotating from rest due to a torque of 1.5 Nm, then its kinetic energy after it complete 20 revolution will be