हल कीजिए - `sin theta + cos theta = 1`

(sin theta-cos theta + 1) / (sin theta + cos theta-1) = (1) / (sec theta-tan theta)

(1+ sin theta - cos theta )/( 1+ sin theta + cos theta ) + (1+ sin theta + cos theta )/( 1+ sin theta - cos theta ) =

(1 + sin theta-cos theta) / (1 + sin theta + cos theta) =

What is ( sin theta - cos theta + 1 )/( sin theta + cos theta -1) - ( sin theta + 1 )/( cos theta ) equal to ?

((1 + sin theta-cos theta) / (1 + sin theta + cos theta)) ^ (2) = (1-cos theta) / (1 + cos theta)

(sin theta-cos theta + 1) / (sin theta + cos theta-1) = sec theta + tan theta

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)