Chords AB and CD of a circle intersect inside the circle at point E . If AE = 5.6, EB = 10, CE = 8,find ED.

Chords AB and CD of a circle interset inside the circle at point E. If AE = 5.6 , EB = 10 cm , CE = 8 ,find ED.

Theorem of external division of chords. If secants containing chords AB and CD of a circle intersect outside the circle in point E, then AE xx EB = CE xx ED Given : (1) A circle with centre O (2) Secants AB and CD intersect at point E outside the circle. To prove : AE xx EB = CE xx DE Construction : Draw seg AD and seg BC

Chords AB and CD of a circle intersect at a point P inside the circle. If AB = 10 cm, AP = 4 cm and PC = 5 cm, then CD is equal to:

Chords AB and CD of a circle intersect externally at P. If AB = 6 cm, CD = 3 am and PD = 5 cm, then the length of PB is ____

Two chords AB and CD of a circle intersect at A, AB is the diameter and CD is bot to AB .AE = 2 cm AB = 10 cm,Find value of ED.

If chords AB and CD of a circle intersect each other at a point inside the circle, prove that : PA xx PB = PC xx PD .

The chords AB and CD of a circle intersect at E. If AE = 12cm, BE = 20.25 cm and CE = 3DE, then the length (in cm) of CE is: एक वृत्त की दो जीवाएँ AB तथा CD एक-दूसरे को E पर काटती हैं | यदि AE = 12 सेमी, BE =20.25 सेमी तथा CE = 3DE है, तो CE की लंबाई ( सेमी में ) कितनी होगी ?