The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length ‘3a’ is: a) `x^2 + y^2 =9a^2` b) `x^2 + y^2 = 16a^2` c)`x^2+y^2=4a^2` d)`x^2+y^2=a^2`

The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is: a x^(2)+y^(2)=9a^(2) b) x^(2)+y^(2)=16a^(2) c) x^(2)+y^(2)=4a^(2) d) x^(2)+y^(2)=a^(2)

The equation of circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=a^(2)x^(2)+y^(2)=4a^(2)x^(2)+y^(2)=16a^(2)x^(2)+y^(2)=9a^(2)

The equation of the circel with cente at (2,-2) and passing through the centre of the given circle x ^(2) + y^(2) + 2y-3 =0, is

Equation of the circle with centre at (1,-2) , and passing through the centre of the circle x^(2) + y^(2) + 2y - 3 = 0 , is

Find the equation of the circle passing through the vertices of the triangle whose sides are : x - y = 0 , 3x + 2y = 5 and x + 2y = 5 .

The equation of the in-circle of an equilateral triangle is x^(2)+y^(2)+2x-4y-8=0; find the area of the equilateral triangle.

Find the equations of the circles passing through the point (-4,3) and touching the lines x+y=2 and x-y=2

The equation of a diameter of circle x ^(2) + y^(2)-6x + 2y =0, passing through origin is