A body of mass `4 kg` moving with velocity `12 m//s` collides with another body of mass `6 kg` at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 5 kg moving with a velocity 10 m/s collides with another body of the mass 20 kg at, rest and comes to rest. The velocity of the second body due to collision is

A body of mass m moving with velocity 3km//h collides with a body of mass 2m at rest. Now, the coalesced mass starts to move with a velocity

A body A of mass 20 kg collides with another body B of mass 1 kg. then

A body of mass 10 kg moving with speed of 3 ms ^(-1) collides with another stationary body of mass 5 kg As a result, the two bodies stick togethre. The KE of composite mass will be

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body is

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. The lighter block comes to rest after collision. The loss in KE of the system is

A body of mass 20 gm is moving with a certain velocity. It collides with another body of mass 80 gm at rest. The collision is perfectly inelastic. The ratio of the kinetic energies before and after collision of the system is

A body of mass 2kg moving with a velocity of 6 m//s strikes inelastically another body of same mass at rest. The amount of heat evolved during collision is