A two digit number and the number with digits interchanged add up to 143. In the given number the digit in unit's place is 3 more than the digit in the ten's place. Find the original number.

Solve the following word problems : The sum of a two digit number and the number obtained by interchanging the digits is 143. If the digit at the units place is 3 more than the digit at the tens place, find the original number.

The ratio between a two digit number and the sum of the digits of that number is 4:1. If the digit in the unit's place is 3 more than the digit in the ten's place,what is the number?

The ratio between a to digit number and the sum of the digits of that number is 4:1. If the digit in the unit’s place is 3 more than the digit in the ten’s place, then the number is a. 24 b. 63 c. 36 d. 96

The sum of two digit number and the number obtained by reversing the order of its digits is 143. The digit at ten's place is greater than digit at unit's place by 3. Find the original number.

In a three digit number, the digit in the units place is four times the digit in the hundred place. If the digits in the units place and the tens place are interchanged, the new number so formed is 1 more than the original number. If the digit in the hundred place is one third of the digit in the tens place, what is the original number?

In a three-digit number, the digit in the unit's place is four times the digit in the hundred's place. If the digit in the unit's place and the ten's place are inter changed, the new number so formed is 18 more than the original number. If the digit in the hundred's place is one-third of the digit in the ten's place, then what is 25% of the original number?

The ratio of a 2-digit number to the sum of its digits is 7: 1. If the digit in the ten's place is 1 more than the digit in the one's place, then the number is

A two digit number, the digit in the units place is x and ten's place is y. What is the number.