A grindstone has moment of inertia of `6 kg m^(2)`. A constant torque is applied and the grindstone is found to have a speed of `150` rpm, 10 second after satrting from rest. Calculate the torque.

A grindstone has a moment of inertia of 50 kg m^(2) . A constant couple is applied and the grindstome is found to have a speed of 150 rpm 10 s after starting from rest. Calculate the torque applied.

A grindstone Is found to have a angular speed of 150 rpm, 10s after starting from rest. The angular acceleration of the grindstone is

A grindstone has moment of inertia 0.5kgm^2 .What constant torque should be applied so that it attains an angular velocity of 120 rpm in 8sec .

A grindstone of moment of inertia 6 kg m^(2) is found to have a speed of 150 rpm, 10 sec . After starting from rest. Torque applied is

A grindstone of moment of inertia 6 kg m^(2) is found to have a speed of 150 rpm, 10 sec . After starting from rest. Torque applied is

A grindstone has moment of inertia 0.5kgm^2 .What constant torque should be applied so that it attains an angular velocity of 120 rpm in 8sec . In the above case what is the rate at which work is done at the end of 8sec .

The moment of inertia of flywheel is 4 kg m^2 . If a torque of 10 Nm is applied on it, then the angular acceleration produced will be

The moment of inertia of a ring is 0.40 kg m^2 .If it is making 2100 rpm ,What torque is required to stop it in 2 seconds?

Compute the angular acceleration of a wheel having moment of inertia 20kgm^(2) , when a torque of 10Nm is applied on the wheel.