A particle executes a SHM of angular velocity 2 rad/s and maximum acceleration of `8 m//s^(2)`. What is the path length of the oscillator ?

A particle executes a linear S.H.M. of angular velocity 4 rad/s and maximum acceleration of 8 m//s^(2) . What is its path length ?

If a particle executes SHM with angular velocity 3.5 rad/s and maximum acceleration 7.5m//s^(2) , then the amplitude of oscillation will be

A particle is executing linear S.H.M. with a maximum velocity of 50 cm/s and a maximum acceleration of 40 cm//s^(2) . Calculate the amplitude and the period of oscillation.

A particle executing SHM has a maximum speed of 30 cm"/"s and a maximum acceleration of 60 cm"/"s^(2) . The period of oscillation is………..

A particle in SHM has maximum velocity equals to 36 m/s and maximum acceleration of 216 pi m//s^(2) . The time period of SHM will be

A particle executing S.H.M. has a maximum speed of 30 cm//s and a maximum acceleration of 60cm//s^(2) . The period of oscillation is

A particle executing SHM has a maximum speed of 30 cm//s and a maximum acceleration of 60 cm/s^(2) . The period of oscillation is

A particle executing SHM has a maximum speed of 30 cm//s and a maximum acceleration of 60 cm/s^(2) . The period of oscillation is

A particle executing SHM has a maximum speed of 30 cm//s and a maximum acceleration of 60 cm/s^(2) . The period of oscillation is

A particle executive SHM has maximum speed of 0.5ms^(-1) and maximum acceleration of 1.0ms^(-2) . The angular freqyency of Oscillation is