An artificial satellite is orbiting at a height of 1800 km from the earth's surface. The earth's radius is 6300 km and `g=10m/s^(2)` on its surface. What is the radial acceleration of the satellite?

An artificial satellite is orbiting at a height of 1800 km from the surface of earth. What is speed of the satellite ? (R = 6300 km)

An artificial satellite circulating the earth is at a height 3400km from the surface of the earth, if the radius of the earth is 6400km and g=9.8m/s^2 . calculate the orbital velocity of the satellite.

An earth satellite revolves in a circular orbit at a height of 300 km above the earth's surface with a period of 90 min. What is its speed ? Calculate the radial acceleration of the satellite ? Radius of the earth is 6.38 xx 10^6 m.

An artificial satellite is at a height of 35780 km from the Earth's surface .What is the period of revolution of this satellite ?

An artificial satellite is at a height of 35780 km .from the earth's surface. What is the period of revolution of this satellite?

An artificial satellite is at a height of 36,500 km above earth's surface. What is the work done by earth's gravitational force in keeping it in its orbit ?

An artificial satellite is at a height of 36,500 km above earth's surface. What is the work done by earth’s gravitational force in keeping it in its orbit?

A satellite is orbiting the earth at a height of 20000 km from the surface of the earth . Determine the tangential velocity of the satellite.