समीकरण `Fe + H_(2)O rarr Fe_(3)O_(4) + H_(2)` को संतुलित करना ।

When steam is passed over hot iron, hydrogen is liberated and Fe_(3)O_(4) is formed according to the chemical equation 3 Fe + 4 H_(2)O to Fe_(3)O_(4) + 4 H_(2)(g) . In a typical reaction, 56 g iron was consumed. Calculate the following: The mass of Fe_(3)O_(4) formed. (R.A.M. : H = 1, O = 16, Fe = 56)

Balance the equation , Fe + H_(2)O to Fe_(3)O_(4) + H_(2)

रासायनिक समीकरण को संतुलित करना

रासायनिक समीकरण को संतुलित करना

In the following change, 3Fe + 4H_(2)O rarr Fe_(3)O_4 + 4H_2 If the atomic mass of iron is 56, then its equivalent mass will be :

Write the expression for equilibrium constant K_(p) for the reaction, 3 Fe (s) + 4 H_(2)O (g) hArr Fe_(3)O_(4) (s) + 4 H_(2)(g).

For the equilibrium reaction, 3Fe_((s)) + 4H_(2) O_((g)) hArr Fe_(3)O_(4(s)) + 4 H_(2(g)) the relation between K_(p) and K_(c) is