The distance between two points on a stretched string is 20 cm. A pregressive wave of frequency 400 hertz travels on the string with a velocity of `100m//s`. Calculate phase differency between the points.

A simple harmonic progressive wave of frequency 5 Hz is travelling along the positive X- direction with a velocity of 40 m/s . Calculate the phase difference between two points separated by a distance of 0.8 m .

Two points A and B are at a distance of 30 cm on a stretched string. A travelling wave of frequency 300 Hz and velocity 100 m/s is set up in the string. What will be the phase difference between points A and B ?

The distance between two particles on a string is 10 cm. If the frequency of wave propagating in it is 400 Hz and its speed is 100 m/s then the phase difference between the particles will be

The distance between two points differing in phase by 60^(@) on a wave, velocity 360 m./s and frequency 500 Hz is

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5pi . The wave velocity is

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5pi . The wave velocity is

The phase difference between two points separated by 1m in a wave of frequency 120 Hz is 90^(@) . The wave velocity is

A wave of frequency 400 Hz has a phase velocity of 300 m/s The phase difference between two displacement at a certain point at time t= 10^(-3) s is

A wave of frequency 400 Hz has a phase velocity of 300 m/s The phase difference between two displacement at a certain point at time t= 10^(-3) s is