Calculate the pH when equal volume of `0.01 M HA (K_(a) = 10^(-6))` and `10^(-3)M HB (K_(a) = 10^(-5))` are mixed.

pH when equal volume of 0.1 M HA (K_a=10^(-5)) and 1 M HB (K_a=10^(-6)) are mixed ?

Calculate pH of a resultant solution of 0.1 M HA (K_(a)=10^(-6)) and 0.5 M HB (K_(a)=2xx10^(-6)) at 25^(@)C.

Calculate pH of a resultant solution of 0.1 M HA (K_(a)=10^(-6)) and 0.5 M HB (K_(a)=2xx10^(-6)) at 25^(@)C.

Calculate pH of a resultant solution of 0.1 M HA (K_(a)=10^(-6)) and 0.45 M HB (K_(a)=2xx10^(-6)) at 25^(@)C.

Calculate pH of resultant solution of 0.1 M HA + 0.1 M HB [K_a (HA) =2 xx 10^(-5), K_a (HB)=4 xx 10^(-5)]

pH of a 0.01 M solution (K_(a)=6.6xx10^(-4))

pH of a 0.01 M solution (K_(a)=6.6xx10^(-4))

100 ml 0.04 M HA (K_(a)=10^(-5)) and 100 mI 0.8 M HB (K_(a) = 10^(-6)) are mixed together. Which is an incorrect statement ? (Given : (0.6)^(0.5) = 0.78, log (0.78) = -0.108)

Calculate pH solution: 0.1 M CH_(3)COOH (K_a=1.8 xx 10^(-5))