Let P = 0 be the plane, passing through the line of intersection of the planes x + y + 2z - 4 = 0 & 2x - y - 5z + 1 = 0 & parallel to the vector (i+j+k). Then distance of P = 0 from origin is

Let P=0 be the plane,passing through the line of intersection of the planes x+y+2z-4=0 & 2x-y-5z+1=0 & parallel to the vector (hat i+hat j+hat k) Then distance of P=0 from origin is

Let P=0 be the plane,passing through the line of intersection of the planes x+y+2z-4=0&2x-y-5z+1=0 & parallel to the vector (i+j+hat k) .Then distance of P=0 from origin is

The equation of plane passing through the line of intersection of planes x+y+z-2=0,2x+3y+z-4=0 and parallel to X-axis is

The equation of a plane passing through the line of intersection of the planes : x+2y+z-10=0 and 3x+y-z=5 and passing through the origin is :

Let P be thte plane, which contains the line of intersection of the planws, x + y + z -6 =0 and 2x + 3y + z + 5 =0 and it is perpendicular to the xy-plane. Then the distance of the point (0,0,256) from P is equal to (m)/(sqrtn), then the value of m,n is