`A+2B to 2C+D`
The initial conc.of B is 1.5 times the initial conc.of A .At equilibrium, conc.of A is equal to B .The equilibrium constant `K_(c)` is

In a gaseous reaction A+2B iff 2C+D the initial concentration of B was 1.5 times that of A. At equilibrium the concentration of A and D were equal. Calculate the equilibrium constant K_(C) .

In a chemical reaction , A+2Boverset(K)hArr2c+D, the initial concentration of B was 1.5 times of the concentrations of A , but the equilibrium concentrations of A and B were found to be equal . The equilibrium constant (K) for the aforesaid chemical reaction is :

For the reaction A+B hArr C+D , the initial concentrations of A and B are equal. The equilibrium concentration of C is two times the equilibrium concentration of A. The value of equilibrium constant is ………..

The reaction A(aq)+ 2B(aq) harr 2C(aq) + D studied in a one litre vessel at 250^(@)C , K_(C) = 0.5 .The initial concentration of A is '3n',equilibrium concentration of "C" is found to the equal to the equilibrium concentration of "B" .What is the concentration of "D" at equilibrium?