If `(sec theta - 1)(sec theta + 1) = 1/3,`then `cos theta` = …………

(1+sec theta)/sec theta=

If sec theta - tan theta =(a+1)/(a-1), then cos theta =

Prove each of the following identities : (i) (sec theta -1)/(sec theta +1) =(sin^(2) theta)/((1+ cos theta)^(2) ) (ii) (sec theta - tan theta)/(sec theta + tan theta) = (cos^(2) theta)/((1+ sintheta)^(2))

Prove that sqrt((sec theta -1)/( sec theta +1))=(1- cos theta )/( sin theta )

prove that (tan theta) / (sec theta -1) = (tan theta + sec theta + 1) / (tan theta + sec theta - 1)

Prove that (tan theta+ sin theta)/(tan theta-sin theta)= (sec theta+1)/(sec theta-1) OR Prove that (cosec theta- cot theta)^(2)=(1-cos theta)/(1+cos theta)

(1+sec theta - tan theta)/(1+sec theta + tan theta)=

Prove that: (sec theta-1)/(sec theta+1)=((sin theta)/(1+cos theta))^(2)

( sec theta + tan theta -1)/( tan theta - sec theta +1)

Prove that: sqrt((sec theta-1)/(sec theta +1)) + sqrt((sec theta + 1)/(sec theta-1)) = 2 "cosec" theta