दो सदिशों `bar(a)=bar(i)-bar(j)` तथा `bar(b)=bar(j)+bar(k)` के बीच का कोण ज्ञात कीजिए |

Compute [bar(i) - bar(j). bar(j) - bar(k). bar(k) -bar(i)] .

If bar(a)=bar(i)+bar(j)+bar(k) and bar(b)=bar(j)-bar(k) , then find a vector vec( c ) such that bar(a)xx bar( c )=bar(b) and bar(a).bar( c )=3 .

Let bar(a) = 2bar(i)-bar(j)+bar(k), bar(b) = 3bar(i) + 4bar(j) -bar(k) and if theta is the angle between bar(a), bar(b) then find sin theta .

If bar(a)=4bar(i)+6bar(j) and bar(b)=3bar(j)+4bar(k), then the vector form of the component of a along b is

If bar(a)=bar(i)-2bar(j)+bar(k), bar(b)=2bar(i)+bar(j)+bar(k), bar(c ) = bar(i) + 2bar(j)-bar(k) , then find bar(a) xx (bar(b) xx bar(c )) and |(bar(a)xxbar(b))xxbar(c )| .

If bar(a) = 2bar(i) - 3bar(j) + bar(k) and bar(b) = bar(i) + 4bar(j) -2bar(k) , then find (bar(a) + bar(b))xx(bar(a)-bar(b))

If bar(a) = 2bar(i) - bar(j) + bar(k), and bar(b) = bar(i) - 3bar(j) - 5bar(k) then find |bar(a) xx bar(b)| .

If bar(a)=bar(i)+bar(j)+bar(k) and bar(b)=2bar(i)-3bar(j)-bar(k) , find the unit vector in the direction of bar(a)+bar(b) .

Prove that vectors bar(a) = 2bar(i) -bar(j) + bar(k), bar(b) = bar(i) -bar(3j)-5bar(k) and bar(c ) = 3bar(i) - 4bar(j) -4bar(k) are coplanar.