A thin lens of focal length + 12 cm is immersed in water `(mu = 1.33).` What is its new focal length ?

A convex lens of focal length 24 cm is totally immersed in water (n = 1.33). Find its focal length in water (n = 1.5).

A glass (mu=1.5) convex lens of focl length 40 cm is placed in water (mu=1.3) .What will be its new focal length?

A convex lens (n = 1.5) of focal length f_a is immersed in water n = 1.33.

A thin lens made of glass of refractive index mu = 1.5 has a focal length equal to 12 cm in air. It is now immersed in water ( mu=4/3 ). Its new focal length is

A thin lens made of glass of refractive index muu = 1.5 has a focal length equal to 12 cm in air. It is now immersed in water ( mu=4/3 ). Its new focal length is

A convex lens of focal length 12 cm is made of glass of mu=(3)/(2) . What will be its focal length when immersed in liquid of mu=(5)/(4) ?

A convex lens of focal length 12 cm is made of glass of mu=(3)/(2) . What will be its focal length when immersed in liquid of mu=(5)/(4) ?