A potentiometer consists of a wire of length 4 m and resistance `10Omega`. It is connected to a cell of emf 2V.The potential gradient of the wire is

A potentiometer consists of a wire of length 4 m and resistance 10 Omega . If is connected of cell of emf 2V . The potential difference per unit length of the wire will be

A potentiometer consists of a wire of length 4 m and resistance 10 Omega . If is connected of cell of emf 2V . The potential difference per unit length of the wire will be

The potentiometer consists of a wire of length 4 m and resistance of 10Omega . It is connected to a cell of e.m.f. 2 V. The potential difference per unti length of the wire will be

A potentiometer consists of a wire of length 4m. And resistance 10 Omega is connected to cell of emf 2V The potential difference per unit length of wire will be

A cell of e.m.f. 2 volt and negligible internal resistance is connected to potentiometer wire of length 4 m and resistance 25 Omega , to form a closed circuit. Find the potential gradient along the wire .

A potentiometer wire of length 1m has a resistance 20Omega .It is connected in series with a resistance R and a cell of emf 2 volts.If potential gradient is 1V/m .Find R

A current of 1.0 mA is flowing through a potentiometer wire of length 4 m and of resistance 4 Omega , find the potential gradient of potentiometer wire

If a ideal battery of e.m.f.10 V is connected with external resistance 9Omega and a wire of length 10 m and resistance 1Omega in series as shown. Then the potential gradient of wire is