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8 cos^(3) 10^(@) -6 cos 10^(@) =...

`8 cos^(3) 10^(@) -6 cos 10^(@) = `

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8 cos^(3) 20^(@) -6 cos 20^(@) =

I : sin^(2) 42^(@) - sin^(2) 12^(@)=(sqrt(5)+1)/(8) II : 8 cos^(3) 10^(@) - 6 cos10^(@)= sqrt(3)

cos ^(3) 110 ^(@) + cos ^(3) 10^(@) + cos ^(3) 130^(@)=

cos ^(3) 110 ^(@) + cos ^(3) 10^(@) + cos ^(3) 130^(@)=

cos ^ (3) 10 ^ (@) + cos ^ (3) 110 ^ (@) + cos ^ (3) 130 ^ (@) =

i) Prove that: cos^(3)2A+3cos2A = 4(cos^(6)A-sin^(6)A) ii) Prove that: 4(cos^(3)10^(@) + sin^(3)20^(@)) = 3(cos10^(@)+sin20^(@))

cos^(3)110^(@)+cos^(3)10^(@)+cos^(3)130^(@)=

cos^(3)10^(@)+cos^(3)110^(@)+cos^(3)130^(@)=?

If x= cos 10^(@)cos 20^(@) cos 40^(@), then the value of x is.............. A) 1/4 tan 10^(@) B) 1/8 cos 10^(@) C) 1/8 cosec 10^(@) D) 1/8 sec 10^(@)