The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility .
He:144.97 kbar, `H_2`:69.16 kbar, `N_2`:76.48 kbar, `O_2`: 34.86 kbar

The value of Henry's law constant for few gases at 298 K is given below. Arrange these gases in the increasing order of their solubility . N_2 : 76.48 kbar. O_2 : 34.86 kbar, H_2 : 69.16 kbar

Arrange the gases, H_2, CO_2, N_2, O_2 in the decreasing order ..

Arrange the gases, H_2, CO_2, N_2, O_2 in the increasing order of their rate of diffusion.

The values of rate constants of some reactions are given below . Determine the order in each case. k=6.2xx10^(-3)s^(-1)

Arrange the gases, H_(2) , N_(2), He, O_(2) in increasing rate of diffusion.

Arrange the gases, H_(2) , N_(2), He, O_(2) in increasing rate of diffusion.

The Henry's law constant for CO_(2) in water at 298 K is 1.67 kbar. Calculate the solubility of CO_(2) at 298 K when the pressure of CO_(2) is one bar.

The critical temperature of H_(2),NH_(3) and CO_(2) gases are 5K, 405 K and 304 K, respectively. Arrange them in the increasing order of their intermolecular forces of attraction.

The values of the Henry's law constant of Ar, CO_2 , CH_4 ,and O_2 in water at 25^@C are 40.30,1.67,0.41 and 34.86 kbar, respectively, The order of their solubility in water at the same temperature and pressure is

State Henry's law. At the same temperature, CO_2 gas is more soluble in water then O_2 gas. Which one of them will have higher value of K_H ?