The rate law for a reaction between `A` and `B` is given by rate `= k[A]^(n)[B]^(m)`. On doubling the concentration of `A` and halving the concentration of `B`, the ratio of the new rate to the earlier rate of the reaction becomes

The rate law for a reaction between the substances A and B is given by Rate = k[A]^(n)[B]^(m) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:

The rate law for a reaction between the substances A and B is given by Rate = k[A]^(n)[B]^(m) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:

The rate law for a reaction between the substances A and B is given by Rate = k[A]^(n)[B]^(m) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:

The rate law for a reaction between the substances A and B is given by Rate = k[A]^(n) [B]^(m) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate of the earlier rate of the reaction will be as