Consider a binary mixture of volatile liquides. If at `X_(A)=0.4`, the vapour pressure of solution is 580 torr then the mixture could be `(p_A^@=300 "torr" ,P_(B)^@=800 "torr")` :

Consider a binary mixture of volatile liquids . If at X_(A)=0.4 the Vapour pressure of solution is 580 torr than the mixture could be (P_(A)^(0)=300 torr, P_(B)^(0)=800 torr)

Mixture of volatile components A and B has a total vapour pressure (in torr)p= 254-119 x_(A) is where x_(A) mole fraction of A in mixture .Hence P_(A)^@ and P_(B)^@ are(in torr)

Mixture of volatile components A and B has a total vapour pressure (in torr)p= 254-119 x_(A) is where x_(A) mole fraction of A in mixture .Hence P_(A)^@ and P_(B)^@ are(in torr)

Mixture of volatile components A and B has a total vapour pressure (in torr)p= 254-119 x_(A) is where x_(A) mole fraction of A in mixture .Hence P_(A)^@ and P_(B)^@ are(in torr)

Mixture of volatile components A and B has a total vapour pressure (in torr)p= 254-119 x_(A) is where x_(A) mole fraction of A in mixture .Hence P_(A)^@ and P_(B)^@ are(in torr)

Mixture of volatile components A and B has a total vapour pressure (in torr)p= 254-119 x_(A) is where x_(A) mole fraction of A in mixture .Hence P_(A)^@ and P_(B)^@ are(in torr)

The vapour pressure of a liqid solution containing A and B is 99 torr. Colvulate mole % of in vapour phese. (Given : P_(A^(@)) = 100 torr , P_(B^(@)) =80 torr)

Two liquids X and Y are perfectly immisoible. If X and Y have molecular masses in ratio 1:2 , the total vapour pressure of a mixture of X and Y prepared in weight ratio 2:3 should be (P_(X^(0))=400 torr, P_(Y^(0))=200 torr)

Two liquids X and Y are perfectly immisoible. If X and Y have molecular masses in ratio 1:2 , the total vapour pressure of a mixture of X and Y prepared in weight ratio 2:3 should be (P_(X^(0))=400 torr, P_(Y^(0))=200 torr)