A magnet makes `40` oscillations per minute at a place having magnetic field intensity of `0.1xx10^(-5)T`. At another place, it takes 2.5 sec to complete one vibrating. The value of earth's horizontal field at that place is

A magnet makes 40 oscillations per minute at a place having magnetic field of 0.1 xx 10^(-5) T . At another place, " it take 2.5 s to complete one vibration. If the value of the earth's horizontal field at that place is y xx 10^(-6) T . then find y .

A magnet makes 30 oscillations per minute at a place where the field is 0.2xx10^(-4) Tesla , At another place it takes 1.5 sec to complete one oscillation . What is the field at this place.

A magnet makes 30 oscillations per minute at a plane where intensity is 32N//weber . At another place it takes Is to complete one oscillation. The value of horizontal intensity at the seeond place is,

A magnet makes 30 vibrations per minute at a place, where horizontal component of earth's field is 0.18G. At another place if it takes 1.6s to complete one vibration. What is the value of horizontal component of earth s field there? What is the magnetic moment if its moment of inertia is 10^-5 kg m^2 ?

At a certain place, a magnet makes 30 oscillations per minute. At another place, the magnetic field is double. What is the its time period ?

At a certain place a magnet makes 30 oscillations per minute. At another place where the magnetic field is double, its time period will be

At a certain place a magnet makes 30 oscillations per minute. At another place where the magnetic field is double, its time period will be