The displacement -time equation of a particle moving along x -axis is `x=(t^(3))/(3)-(t^(2))/(2)+20`The acceleration -velocity equation of the particle is `a^(2)=KV+1` Then the value of K is

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-

The displacement (in metre) of a particle moving along x-axis is given by x=18t +5t^(2) Calculate (i) instantaneous acceleration.

The displacement (in meter)of a particle, moving along x-axis is given by x=18t + 5t^2 . Calculate instantaneous velocity at t = 2s

The displacement ( in meter ) of a particle moving along x-axis is given by x = 18t+ 5t^2 . Calculate instantaneous velocity at t = 2s

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-2"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is

Displacement-time equation of a particle moving along x-axis is x=20+t^3-12t (SI units) (a) Find, position and velocity of particle at time t=0. (b) State whether the motion is uniformly accelerated or not. (c) Find position of particle when velocity of particle is zero.

Displacement-time equation of a particle moving along x-axis is x=20+t^3-12t (SI units) (a) Find, position and velocity of particle at time t=0. (b) State whether the motion is uniformly accelerated or not. (c) Find position of particle when velocity of particle is zero.