A heat engine has an efficiency `eta`.Temperatures of source and sink are each decreased by 100 K. The efficiency of the engine

A heat engine has an efficiency eta . Temperatures of source and sink are each decreased by 100K. Then, the efficiency of the engine

The efficiency of a carnot heat engine is 0.6 when the absolute temperatures of the source and sink are T_(1) and T_(2) respectively. The efficiency of another carnot engine is also 0.6 but the source and sink temperatures are different. What are the temperatures of the source and the sink of the other engine ?

A cannot engine has efficiency (1)/(6) . If temperature of sink is decreased by 62^(@)C then its efficiency becomes (1)/(3) then the temperature of source and sink:

A cannot engine has efficiency (1)/(6) . If temperature of sink is decreased by 62^(@)C then its efficiency becomes (1)/(3) then the temperature of source and sink:

The efficiency of carnot heat engine is 25%. When the temperature of the source alone is raised by 100K, the efficiency becomes 50%. Find the temperature of the source and the sink.

An ideal heat engine working between temperature T_(H) and T_(L) has efficiency eta . If both the temperature are raised by 100 K each the new efficiency of heat engine will be