Two light waves are represented by `y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta)`. The phase of the resultant wave is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)

Two coherent waves are represented by y_(1)=a_(1)cos_(omega) t and y_(2)=a_(2)sin_(omega) t. The resultant intensity due to interference will be

Two coherent waves are represented by y_(1)=a_(1)cos_(omega) t and y_(2)=a_(2)sin_(omega) t. The resultant intensity due to interference will be

The displacements of two intering lightwaves are y_(1) = 4 sin omega t and y_(2) = 3 cos(omega t) . The amplitude of the resultant wave is ( y_(1) and y_(2) are in CGS system)