When we saw him last, he ran to catch a bus.

A person is standing at a distance 's' m from a bus. The bus begins to move with cosntant acceleration 'a' m//s^(2) away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

A passenger is standing d metres away from a bus. The bus begins to move eith constat acceleration a. To catch the bus the passenger runs at a constant speed (v) towards the bus, at what minimum speed he must have ,so that he may catch the bus.

A bus begins to move with an acceleration of 1 ms^(-1) . A man who is 1 48m behind the bus starts running at 10 ms^(-1) to catch the bus, the man will be able to catch the bus after .

A man runs at a speed of 4 ms to overtake a standing bus. When he is 6m behind the door (a ) the bus moves forward and continues moving with constant acceleration of 1.2 m/s^2 . The time after which the man is able to catch the bus is :