If `(1+i)z=(1-i)bar z` then z is

If (1+i)z=(1-i) (bar z) , then show that z=-i bar z

Select and write the correct answer from the given alternatives in each of the following: If (1 + i) z = 1 (1 - i) bar z , then z is

If z_(2) be the image of a point z_(1) with respect to the line (1-i)z+(1+i)bar(z)=1 and |z_(1)|=1 , then prove that z_(2) lies on a circle. Find the equation of that circle.

If z_(2) be the image of a point z_(1) with respect to the line (1-i)z+(1+i)bar(z)=1 and |z_(1)|=1 , then prove that z_(2) lies on a circle. Find the equation of that circle.

If z is a complex number then radius of the circle zbar(z)-2(1+i)z-2(1-i)bar(z)-1=0 is

Find the radius and centre of the circle z bar(z) + (1-i) z + (1+ i) bar(z)- 7 = 0

If z_(1)=2-i, z_(2)=1+ 2i, then find the value of the following : (i) Re((z_(1)*z_(2))/(bar(z)_(2))) (ii) Im (z_(1)*bar(z)_(2))

If z_(1)=2-i, z_(2)=1+ 2i, then find the value of the following : (i) Re((z_(1)*z_(2))/(bar(z)_(2))) (ii) Im (z_(1)*bar(z)_(2))

If (3+i)(z+bar z)-(2+i) (z- bar z)+14i=0 , then z bar z =