A charged particle enters in a uniform magnetic field perpendicular to it. Now match the following two columns.

A charged particle enters a uniform magnetic field perpendicular to it. The magnetic field

A charged particle enters a uniform magnetic field perpendicular to it. The magnetic field

A charged particle moves thorugh a uniform magnetic field perpendicular to its direction. Then

A charged particle enters into a uniform magnetic field with velocity v_(0) perpendicular to it , the length of magnetic field is x=sqrt(3)/(2)R , where R is the radius of the circular path of the particle in the field .The magnitude of charge in velocity of the particle when it comes out of the field is

When a charged particle enters a uniform magnetic field its kinetic energy

When a charged particle enters a uniform magnetic field its kinetic energy

When a charged particle enters a uniform magnetic field its kinetic energy

A charged particle enters a uniform magnetic field with velocity v_(0) = 4 m//s perpendicular to it, the length of magnetic field is x = ((sqrt(3))/(2)) R , where R is the radius of the circular path of the particle in the field. Find the magnitude of charge in velocity (in m/s) of the particle when it comes out of the field.