A CE amplifier, has a power gain of 40 dB. The input resistance and output load resistance are `500Omega and 2kOmega` respectively. Find the value of common - emitter current gain.
`["take gain in dB "=10log((P_("out"))/(P_("in")))]`

An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100 Omega and the output load resistance is 10 kOmega .The common emitter current gain beta is :

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A npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100 Omega and the output load resistance is 10 k Omega . The common emitter current gain beta is:

An npn transistor operates as a common emitter amplifier with a power gain of 10^6 . The input circuit resistance is 100 Omega and the output load resistance is 10 k Omega . The common emitter current gain ' beta ' will be (Round off to the Nearest Integer)

For a common emitter amplifier, the voltage gain is 40. Its input and output impedances are 100 Omega and 400 Omega respectively. The power gain of the C.E. amplifier will be

AC current gain for transistor in common emitter amplifier is 20. If input and output resistances are 2 k Omega and 5 K Omega respectively, find: Power gain

A CE amplifier has current gain 50. Load resistance is 4 k Omega and input resistance is 500 Omega . 10 mV ac signal is applied. Peak value of output signal is