The differaction of barium with X-cadiation of wavelength `227` pm given a first - order differaction at `30^(@)` .Thus , distance between the two plannes is

The diffraction of a crystal with X-ray of wavelength 2.31A^@ gives a first order reflection at 28^@9′ . What is the distance between the diffracted planes.

The diffraction of a crystal with X-ray of wavelength 2.31A^@ gives a first order reflection at 28^@.9′ . What is the distance between the diffracted planes.

The diffraction of a crystal with X-ray of wavelength 2.31A^@ gives a first order reflection at 28^@.9′ . What is the distance between the diffracted planes.

The diffraction of a crystal with X-ray of wavelength 2.31A^@ gives a first order reflection at 28^@.9′ . What is the distance between the diffracted planes.

The diffraction of crystal of Ba with X-ray of wavelength 2.29Å gives a first order reflection at 27^(@)8' . What is the distance between the diffracted patterns ?

When a crystal surface is exposed to X-rays of 250 pm wave length, the first order reflection occurs at 30^(@) . The interplanar distance of the planes producing this reflection is

Monochromatic X-rays, when reflected from a crystal with lattice spacing 2.0 Å , produce first order diffraction maximum at theta=30^(@) . What is the wavelength of X-rays ?

X rays of wavelength lambda = 0.134nm . Gave a first order diffraction from the surface of the crystal value was found to be 10.5^(@) , calculate the distance between the plane in the crystal.

A sample of a crystalline solid scatters a beam of X-rays of wavelength 70.93 pm at an angle 2 theta of 14.66^(@) . If this is a second-order reflection (n = 2), calculate the distance between the parallel planers of atoms from which the scattered beam appears to have been reflected.