[2x-3y+13=0],[3n-2y+12=0]

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

Solve the following system of equations graphically: 2x-3y+13=0;quad 3x-2y+12=0

Solve the following system of equations : 2x-3y+13=0;\ \ \ 3x-2y+12=0

{:(2x - 3y = - 13),(3x - 2y = - 12):}

Show that the area of the parallelogram formed by the lines 2x-3y+a=0,\ 3x-2y-a=0,\ 2x-3y+3a=0\ a n d\ 3x-2y-2a=0\ is(2a^2)/5s qdotu n i t sdot

Answer each question by selecting the proper alternative from those given below each question so as to make the statement true: x = 2, y = 3 is a solution of linear equation …………. a) 2x+3y-13=0 , b) 3x+2y-13=0 , c) 2x-3y+13=0 , d) 2x+3y+13=0

Show that the lines 2x+3y+11=0 and 2x-2y-1=0 are conjugate with respect to the circle x^(2)+y^(2)+4x+6y-12=0

Solve: {:(2x - 3y = - 13),(3x - 2y = - 12):}

The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0

{:(2x + 3y + 5 = 0),(3x - 2y - 12 = 0):}