`sintheta+sin2theta+sin3theta=1+costheta+cos2theta`

If sintheta-3sin2theta+sin3theta=costheta-3cos2theta+cos3theta , then one of the general value is:

(sin5theta+sin2theta-sintheta)/(cos5theta+2cos3theta+2cos^2theta+costheta) is equal to

Prove that (sin theta+ sin 2theta + sin 3 theta)/(costheta+cos2theta+cos3theta)=tan 2 theta

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta)

costheta-cos2theta=sin3theta

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

Prove the following : (sintheta+sin3theta+sin5theta+sin7theta)/(costheta+cos3theta+cos5theta+cos7theta) = tan4theta

(sintheta+sin2theta)/(1+costheta+cos2theta) =