A body of mass `5 xx 10^(3) g` kg moving with speed 2 m/s collides with a body of mass `15 xx 10^(3) kg` inelastically & sticks to it. Then loss in K.E. of the system will be :

A body of mass 5 xx 10^(3) kg moving with speed 2 m/s collides with a body of mass 15 xx 10^(3) kg inelastically & sticks to it. Then loss in K.E. of the system will be :

A body of mass 10 kg moving with speed of 3 ms ^(-1) collides with another stationary body of mass 5 kg As a result, the two bodies stick togethre. The KE of composite mass will be

A body of mass 10 kg moving with speed of 3 ms ^(-1) collides with another stationary body of mass 5 kg As a result, the two bodies stick togethre. The KE of composite mass will be

A body of mass 5 kg moving with a velocity 10 m/s collides with another body of the mass 20 kg at, rest and comes to rest. The velocity of the second body due to collision is

Solve the following examples: (numerical problems) A body of mass 1 kg, moving with a velocity of 4 m/s collides with a body of mass 0.5 kg moving with a velocity of 2 m/s . If the velocity of the first body after collision is 8/3 m/s , find the velocity of the second body after collision.

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is