" 14."3t^(2)+5t

What is the acceleration at the end of 3s of the particle that moves with the rule S = 3t^(2) + 5t + 2 ?

What must be added to 11t^(3)+5t^(4)+6t^(5)-3t^(2)+t+5 , so that the resulting polynomial is exactly divisible by 4-2t+3t^(2) ?

What must be added to 11t^(3)+5t^(4)+6t^(5)-3t^(2)+t+5 , so that the resulting polynomial is exactly divisible by 4-2t+3t^(2) ?

The x and y coordiates of a particle at any time t are given by x = 7t + 14 t^(2) and y = 5t, where x and y are in metre and t is in second. The acceleration of the particle at t = 5 s is

Let the function y = f(x) be given by x= t^(5) -5t^(3) -20t +7 and y= 4t^(3) -3t^(2) -18t + 3 where t in ( -2,2) then f'(x) at t = 1 is

Let the function y = f(x) be given by x= t^(5) -5t^(3) -20t +7 and y= 4t^(3) -3t^(2) -18t + 3 where t in ( -2,2) then f'(x) at t = 1 is

Find the value of each of the following polynomials at the indicated value of variables : p(t) = 4t^(4) + 5t^(3) - t^(2) + 6 at t = a.

If t+1/t =5, then (2t)/(3t^(2)-5t+3) is equal to ……..

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the time when the acceleration is 14ft/ sec^2