When the current flowing in a circular coil is doubled and the number of turns of the coil in it is halved , the magnetic field at its centre will become

If the current (I) flowing through a circular coil, its radius (R ) and number of turns (N) in it are each doubled, magnetic flux density at its centre becomes:

The radius and number of turns of a circular coil are doubled. The magnetic intensity at its centre will be

A current I produces a magnetic field B at the centre of the circular coil. If the coil rewound to double its number of turns then what is the magnetic field at its centre in terms of B?

When the radius of a circular current carrying coil is doubled and current in it is halved, the magnetic dipole moment of coil originally 4 units become.

The current through a circular conducting coil be doubled and the radius be halved then what change of magnetic field takes place in the centre of the coil?

The magnetic field at the centre of a circular coil carrying current I-ampere is B. If the coil bent into smaller circular coil of n turns, its magnetic field at the centre is B. The ratio between B’ and B is:

If B is the magnetic field produced at the centre of a circular coil of one turn of length L carrying current I the what is the magnetic field at the centre of the same coil which is made into 10 turns ?

The radii of two circular coils are 5 cm and 10 cm and their number of turns are 40 and 100, respectively. The coils are coplanar and concentric and a 4 A current is sent through the first coil. Find the current and its direction through the second coil so that the magnetic field at thier centre becomes zero?

Current I A flowing in a circular coil of radius r. then the magnetic induction at the centre is B. If the current is doubled then the magnetic induction will be