{tan^(-1)(x)/(1+x^(2))+tan^(-1)(1+x^(2))/(x)}

The vlaue of the integral int_(-1)^(3) ("tan"^(1)(x)/(x^(2)+1)+"tan"^(-1)(x^(2)+1)/(x))dx is equal to

The value of int_(0)^(4)[tan^(-1)((x)/(x^(2)+1))+tan^(-1)((x^(2)+1)/(x))]dx is

The value of the integral underset(-1)overset(3 )int ("tan"^(1)(x)/(x^(2)+1)+"tan"^(-1)(x^(2)+1)/(x))dx is equal to

The value of the integral underset(-1)overset(3 )int ("tan"^(1)(x)/(x^(2)+1)+"tan"^(-1)(x^(2)+1)/(x))dx is equal to

If y=tan^(-1).(1)/(1+x+x^(2))+tan^(-1).(1)/(x^(2)+3x+3) upto +tan^(-1).(1)/(x^(2)+5x+7)+….+2n terms (AA x ge0), then y(0) is

If =tan^(-1)(1)/(1+x+x^(2))+tan^(-1)(1)/(x^(2)+3x+3)+tan^(-1)(1)/(x^(2)+5x+7)+ upto n terms,then find the value of y'(0) .

int_(-1)^(3)(Tan^(-1)""(x)/((x^(2)+1))+Tan^(-1)""(x^(2)+1)/(x))dx=

Evaluate: int_(-1)^3(tan^(-1)(x/(x^2+1))+tan^(-1)((x^2+1)/x))dx

int _ (-2)^(1) (tan^(-1) ((x)/(x^(2) +1))+tan^(-1) ((x^(2) +1)/( x))) dx is (i) (pi)/(2) (ii)-(pi)/(2) (iii) pi (iv) -pi

If: tan^(-1)((x-1)/(x+1))+ tan^(-1)((2x-1)/(2x+1)) = tan^(-1) (23/36) . Then: x=