[" Solution "7:],[" Given,"x=(sin^(3)t)/(sqrt(cos2t))" and "y=(cos^(3)t)/(sqrt(cos2t))]

x = (sin^3t)/(sqrt(cos 2t)), y = (cos^3 t)/(sqrt(cos 2t)) .

If x=(sin^(3)t)/(sqrt(cos2t)) and y=(cos^(3)t)/(sqrt(cos2t)) , then find (dy)/(dx) .

Find (dy)/(dx) , if x=(sin^3t)/(sqrt(cos2t)) , y=(cos^3t)/(sqrt(cos2t))

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=(sin^(3)t)/(sqrt(cos2t)),y=(cos^(3)t)/(sqrt(cos2t))

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find (dy)/(dx) . x= (sin^(3)t)/(sqrt(cos 2t)), y= (cos^(3)t)/(sqrt(cos 2t)) .

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find (dy)/(dx) . x= (sin^(3)t)/(sqrt(cos 2t)), y= (cos^(3)t)/(sqrt(cos 2t)) .

Find dy/dx x=cos^(3)t/sqrtcos2t , y = sin^(3)t/sqrt cos2t