[XeF_(4)+O_(2)F_(2)rarr'P'+O_(2)],[" Hybridisation of "'Xe'" in "'P'" is : "]

XeF_(4)+O_(2)F_(2) to

XeF_(4)+O_(2)F_(2) to

XeF_(4)+O_(2)F_(2) to 'P'+O_(2) Hybrisation of 'Xe' in P is

Hybridisation of Xe in XeF_4 , is

Hybridisation of xe in xe F_2 :

XeF_(4)+H_(2)O to

Hybridisation of oxygen in O_(2)F_(2)

(a) Complete the following chemical equations : (i) NaOH + Cl_(2) rarr ("hot and cone.") (ii) XeF_(4) + O_(2)F_(2)rarr (b) Draw the structure of the following molecules : (i) H_(3)PO_(2) (ii) H_(2)S_(2)O_(7) (ii) XeOF_(4)

(a) Complete the following chemical equations : (i) NaOH + Cl_(2) rarr ("hot and cone.") (ii) XeF_(4) + O_(2)F_(2)rarr (b) Draw the structure of the following molecules : (i) H_(3)PO_(2) (ii) H_(2)SO_(2)O_(7) (ii) XeOF_(4)

Xe reacts with F_(2) at different ratio to give different types of xenon fluorides. Xe+ Fe rarr XeF_(2) (2:1) Xe +F_(2) rarr XeF_(4) (1:5) Xe + F_(2) rarr XeF_(6) (1: 20) The sbape and hybridisation of XeF_(4 ) is