" (ii) "(1)/(sqrt((1-16x^(2))))

int(1)/(sqrt(1-16x^(2)))

int1/(sqrt(1-16x^2))

Evaluate: (i) int(1)/(sqrt(9-25x^(2)))dx (ii) int(1)/(sqrt(16x^(2)+25))dx

int(dx)/(sqrt(1-16x^2) =

if int (1)/(sqrt(9-16x^(2)))dx=alpha sin ^(-1) (beta x) +c. then alpha +(1)/(beta )=

int (dx)/(sqrt(16x^(2)+25))

If int(1)/(sqrt(9-16x^(2)))dx=alphasin^(-1)(betax)+c , then alpha+(1)/(beta)=

If int(1)/(sqrt(9-16x^(2)))dx=alphasin^(-1)(betax)+c , then alpha+(1)/(beta)=

(d)/(dx)[cos^(-1)(x sqrt(x)-sqrt((1-x)(1-x^(2))))]=(1)/(sqrt(1-x^(2)))-(1)/(2sqrt(x-x^(2)))(-1)/(sqrt(1-x^(2)))-(1)/(2sqrt(x-x^(2)))(1)/(sqrt(1-x^(2)))+(1)/(2sqrt(x-x^(2)))(1)/(sqrt(1-x^(2)))0 b.1/4c.-1/4d none of these

Integrate the functions (1)/(sqrt(16-25x^(2)))