A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of irons is `rho_(1)`, that of mercury is `rho_(M)`. The depth to which the cube sinks is given by the expression

Three cubes of iron whose edges are 6cm,8cm and 10cm respectively formed into a single cube.The edge of the new cube is

A cube of side length 3cm weighs 12kg .What is the weight of similar cube of same material whose side length is 12cm?

A cubical block of steel of each side equal to 1 is floating on mercury in vessel. The densities of steel and mercury are rho_(s) " and " rho_(m) . The height of the block above the mercury level is given by

A cubical block of steel of each side equal to 1 is floating on mercury in vessel. The densities of steel and mercury are rho_(s) " and " rho_(m) . The height of the block above the mercury level is given by

Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is

A piece of iron floats in mercury. Given that the density of iron is 7.8xx10^(3) "kg"m^(-3) and that of mercury is 13 xx 10^(3) "kgm"^(-3) , Calculate the fraction of the volume of iron piece that remains outside the mercury.

Each side of an iron cube is 5 cm. This cube floats on mercury. What height of the cube remains above the surface of mercury? To cover the cube, if water is poured over mercury, then what will be the height of the water column? The density of iron is 7.2g*cm^(-3) and the density of mercury is 13.6g*cm^(-3) .