[" 16.The vectors from origin to the points "A" and "B" are "vec A=3i-6j+2k" and "vec B=2i+bar(j)-2dot k],[" respectively.The area of the triangle "OAB" be "]

The vectors from origin to the point A and B are, vec a = 2i-3j+2k, vec b = 2i +3j +k respectively, then the area of triangle OAB is

The vector from origion to the point A and B are vec(A)=3hat(i)-6hat(j)+2hat(k) and vec(B)=2hat(i)+hat(j)-2hat(k) ,respectively. Find the area of the triangle OAB.

The vector from origion to the point A and B are vec(A)=3hat(i)-6hat(j)+2hat(k) and vec(B)=2hat(i)+hat(j)-2hat(k) ,respectively. Find the area of the triangle OAB.

The vectors from origin to the points A and B are vec(a)=2hat(i)-3hat(j)+2hat(k) and vec(b)=2hat(i)+3hat(j)+hat(k) respectively then the area of triangle OAB is

The vectors from origin to the points A and B are vec(a)=3hat(i)-6hat(j)+2hat(k) and vec(b)= 2hat(i) +hat(j)-2hat(k) respectively. Find the area of : (i) the triangle OAB (ii) the parallelogram formed by vec(OA) and vec(OB) as adjacent sides.

The vectors from origin to the points A and B are vec(a)=3hat(i)-6hat(j)+2hat(k) and vec(b)= 2hat(i) +hat(j)-2hat(k) respectively. Find the area of : (i) the triangle OAB (ii) the parallelogram formed by vec(OA) and vec(OB) as adjacent sides.

If the vectors from the origin to the points A and B are . vec a= a hati-3 hatj+2 hat k and vec b=2hat i + 3hat j + hatk respectively, then the area of triangle OAB Is

The vectors from origin to the points A and B are vec(a)=3hat(i)-6hat(j)+2hat(k) and vec(b)= 2hat(i) +hat(j)-2hat(k) respectively. Find the area of : (i) the triangle OAB (ii) the parallelogram formed by (OA) and (OB) as adjacent sides.

The vectors from origin to the points A and B are vec(a) = 2 hat(i) - 3 hat(j) + 2 hat(k) and vec( b) = 2 hat(i) + 3 hat(j) + hat(k) , respectively, then the area ( in sq. units ) of Delta ABC is

The position vectors of the points A and B are vec i + 2 vec j + 3 vec k and 2 vec i - vec j - vec k respectively. Find the projection of vec (AB) on the vector vec i + vec j + vec k . Also find the resolved part of vec (AB) in that direction.