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1^(2)+4^(2)+7^(2)+..." to "n" terms "=...

1^(2)+4^(2)+7^(2)+..." to "n" terms "=

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If S_(n)=(1.2)/(3!)+(2.2^(2))/(4!)+(3.2^(2))/(5!)+...+ up to n terms, then sum of infinite terms is

If S_(n)=(1.2)/(3!)+(2.2^(2))/(4!)+(3.2^(2))/(5!)+...+ up to n terms, then sum of infinite terms is

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{:("If",a = 1 + 2 + 4 + ..."to n terms"),(,b = 1 + 3 + 9 + ..."to n terms"),(,c =1 + 5 + 25+ ..."to n terms"):} then |(a,2b,4c),(2,2,2),(2^(n),3^(n),5^(n))|=

{:("If",a = 1 + 2 + 4 + ..."to n terms"),(,b = 1 + 3 + 9 + ..."to n terms"),(,c =1 + 5 + 25+ ..."to n terms"):} then |(a,2b,4c),(2,2,2),(2^(n),3^(n),5^(n))|=

{:("If",a = 1 + 2 + 4 + ..."to n terms"),(,b = 1 + 3 + 9 + ..."to n terms"),(,c =1 + 5 + 25+ ..."to n terms"):} then |(a,2b,4c),(2,2,2),(2^(n),3^(n),5^(n))|=

{:("If",a = 1 + 2 + 4 + ..."to n terms"),(,b = 1 + 3 + 9 + ..."to n terms"),(,c =1 + 5 + 25+ ..."to n terms"):} then |(a,2b,4c),(2,2,2),(2^(n),3^(n),5^(n))|=

Find: (4-(1)/(n))+(7-(2)/(n))+(10-(3)/(n))... upto n terms