Coordinates of a point which is at 3 units distance from the point (1-3) on the line 2x + 3y + 7 = 0 is/are

Given a line 2x + 3y = 6, then the possible coordinate of a point P, which is at a distance of 3 units from the point (3,0) on the line is

The coordinates of the point Q symmetric to the point P(–5, 13) with respect to the line 2x – 3y – 3 = 0 are -

The coordinates of the foot of the perpendicular drawn from the point (3,4) on the line 2x +y-7 =0 are

Distance of point (1,3) from the line 2x-3y+9=0 along x-y+1=0

Distance of point (1,3) from the line 2x-3y+9=0 along x-y+1=0

Distance of point (1,3) from the line 2x-3y+9=0 along x-y+1=0

Find the coordinates of the point at unit distance from the lines 3x-4y + 1 = 0, 8x +6y +1 = 0

Find the coordinates of the point at unit distance from the lines 3x-4y + 1 = 0, 8x +6y +1 = 0

The coordinates of the two points lying on x + y = 4 and at a unit distance from the straight line 4x + 3y =10 are