27." यदि "sin^(-1)x+tan^(-1)x=(pi)/(2)" ,तो रिद्ध करीजि कि ":2x^(2)+1=sqrt(5)" ."

If sin^(-1)x+tan^(-1)x=(pi)/(2) , prove that : 2x^(2)+1=sqrt(5)

If sin^(-1)x + tan ^(-1) x = (pi)/(2) , then prove that 2x^(2) + 1 = sqrt(5)

If sin^(-1)x + tan ^(-1) x = (pi)/(2) , then prove that 2x^(2) + 1 = sqrt(5)

If sin^(-1)x+tan^(-1)((1)/(2))=(pi)/(2) then x=

If tan^(-1)(1+x)+tan^(-1)(1-x)=(pi)/(6), then prove that x^(2)=2sqrt(3).

If f(x)=(sin^(-1)x+tan^(-1)x)/(pi)+2sqrt(x), then the range of f(x) is

Solve : (i)" "tan^(-1). x/2 +tan^(-1). x/3 = pi/4 , sqrt(6) gt x gt 0 (ii)" "sin(sin^(-1) . 1/5+cos^(-1)x)=1

cos^(-1)x = tan^(-1)x , then: a. x^2=((sqrt(5)-1)/2) b. x^2=((sqrt(5)+1)/2) c. sin(cos^(-1)x)=((sqrt(5)-1)/2) d. tan(cos^(-1)x)=((sqrt(5)-1)/2)

Solve for x:2tan^(-1)(sin x)=tan^(-1)(2sec x),x!=(pi)/(2)