A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth's magnetic field is `3xx10^(-5)T`. The current required to producea defection of `45^(@)` in it, is

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is B_H = 3 xx 10^(-5) T . Find the current which gives a diflection of 45^@) .

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is B_H = 3 xx 10^(-5) T . Find the current which gives a diflection of 45^) .

A tangent galvanometer has a coil of 50 turns and a radius of 20 cm The horizontal component of the earth's magnetic field is B_(H)=3 xx 10^(-5)T . Find the current (in ampere) which gives a deflection of 45^(circ) . (Take pi=3 )

A tangent galvonnometer has a coil 50turns and a radius of 20cm. The horizontal component of earth's magnetic field is B_(H)=3xx10^(-5) . What will be the current which gives a deflection of 45^(@) ?

A coil of a tangent galvanometer of diametre 0.24 m has 100 turns. If the horizontal component of Earth's magnetic field is 25 xx 10^(-6) T then, calculate the current which gives a deflection of 60^(@) .

The horizontal component of earth's magnetic field is 3 xx 10^(-4) T. The magnetic dip angle is 45°. Find the vertical component.