`Au(s) hArr Au (l)`
above mentioned equilibrium is fovoured at

Fe(l)hArrFe(s) Above equilibrium is favoured at :

Au(s)hArrAu(l) The formation of liquid is favoured at

Use the standard potentials of the couples Au^(+)//Au(+1.69V),Au^(3+)//Au(+1.40V), and Fe^(3+)//Fe^(2+)(+0.77V) to calculate the equilibrium constant for the reaction 2Fe^(2+)(aq)+Au^(3+)(aq) leftrightarrow2Fe^(3+)(aq)+Au^(+)(aq)

Use the standard potentials of the couples Au^(+)//Au(+1.69V),Au^(3+)//Au(+1.40V), and Fe^(3+)//Fe^(2+)(+0.77V) to calculate the equilibrium constnat for the reaction 2Fe^(2+)(aq)+Au^(3+)(aq) leftrightarrow2Fe^(3+)(aq)+Au^(+)(aq)

Consider the following equilibria: I. A(s) hArr B(s), II. A(s) hArr B(l) III. A(l) hArr B(l), IV. A(g) hArr B(g) Which of the above will be disturbed by an increase in pressure?

Consider the following equilibria: I. A(s) hArr B(s), II. A(s) hArr B(l) III. A(l) hArr B(l), IV. A(g) hArr B(g) Which of the above will be disturbed by an increase in pressure?

Starting with 250 ml of Au^(3+) solution 250 ml of Fe^(2+) solution, the following equilibrium is established Au^(3+) (aq) +3Fe^(2+)(aq) hArr 3Fe^(3+) (aq) +Au(s) At equilibrium the equivalents of Au^(3+), Fe^(2+), Fe^(3+) and Au are x,y,z and w respectively. Then:

Starting with 250 ml of Au^(3+) solution 250 ml of Fe^(2+) solution, the following equilibrium is established Au^(3+) (aq) +3Fe^(2+)(aq) hArr 3Fe^(3+) (aq) +Au(s) At equilibrium the equivalents of Au^(3+), Fe^(2+), Fe^(3+) and Au are x,y,z and w respectively. Then:

Starting with 250 ml of Au^(3+) solution 250 ml of Fe^(2+) solution, the following equilibrium is established Au^(3+) (aq) +3Fe^(2+)(aq) hArr 3Fe^(3+) (aq) +Au(s) At equilibrium the equivalents of Au^(3+), Fe^(2+), Fe^(3+) and Au are x,y,z and w respectively. Then: