In the figure , chords PQ and RS intersect at point T outside the circle then by theorem of external division of chords,
`PT xx square = ST xx square `

Chords AB and CD intersect at point M inside the circle then theorem of internal division of chords. AM xx BM = square xx square

In the given figure, chords PQ and RS intersect each other at point L. Find the lenth of RL.

In the given figure, chords PQ and RS intersect each other at point L Find the length of RL.

In the adjoining figure,chord PQ and chord AB intersect at point M.If PM=AM,then prove that BM=QM.

In the adjoining figure, chord Pq and chord AB intersect at pointM . If PM = AM, then prove that BM = QM.

Theorem of internal division of chords. Suppose two chords of a circle intersect each other in the interior of the circle, then the product of the lengths of the two segments of one chord is equal to the product of the lengths of the two segments of the other chord. Given : (1) A circle with centre O . (2) chords PR and QS intersect at point E inside the circle. To prove : PE xx ER = QE xx ES Construction : Draw seg PQ and seg RS

If chords AB and CD of a circle intersect each other at a point inside the circle, prove that : PA xx PB = PC xx PD .

In a circle, two chords PQ and RS bisect each other. Then PRQR is _____________.

In the figure, chords PQ and RS intersect at T as shown. If /_PSR=42^(@) and m(arc SQ)= 42^(@) , then /_STQ="……."